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(lemmy.world)
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this post was submitted on 13 Aug 2023
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I'm a little sad nobody has done the correct math and it's been too long for me to do it off the top of my head lol.
A^2+B^2=C^2? What distance are the diagonals if the sides are 6' apart?
6x6 + 6x6 = sqrt72 = 8.49' !
I did it bois. Ty calculator for sqrt72...
Now do the conversion factor from feef to feet!
The diagonal is 6ft. The side is 6 ft. So 6² + 6feef² = 6²
1 feef = 0ft
Now, what's the length of the sides if the diagonals are 6ft?
Thats easy.
6 * 6 = 36
36 = a² + b²
Lets assume a = b
So a² = 18 = b²
a = b = 4,2426406871
What if every initial value is unknown?
Roughly 4.24?
8.49'!~=116699.97'
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