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Day 4: Ceres Search

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[-] ace@lemmy.ananace.dev 1 points 2 weeks ago

I tried to think of some clever LINQ to do this one, but was blanking entirely.

So naΓ―ve search it is.

C#

string wordsearch = "";
int width;
int height;

public void Input(IEnumerable<string> lines)
{
  wordsearch = string.Join("", lines);
  height = lines.Count();
  width = lines.First().Length;
}

public void Part1()
{
  int words = 0;
  for (int y = 0; y < height; y++)
    for (int x = 0; x < width; x++)
      words += SearchFrom(x, y);

  Console.WriteLine($"Words: {words}");
}
public void Part2()
{
  int words = 0;
  for (int y = 1; y < height - 1; y++)
    for (int x = 1; x < width - 1; x++)
      words += SearchCross(x, y);

  Console.WriteLine($"Crosses: {words}");
}

public int SearchFrom(int x, int y)
{
  char at = wordsearch[y * width + x];
  if (at != 'X')
    return 0;

  int words = 0;
  for (int ydir = -1; ydir <= 1; ++ydir)
    for (int xdir = -1; xdir <= 1; ++xdir)
    {
      if (xdir == 0 && ydir == 0)
        continue;

      if (SearchWord(x, y, xdir, ydir))
        words++;
    }

  return words;
}

private readonly string word = "XMAS";
public bool SearchWord(int x, int y, int xdir, int ydir)
{
  int wordit = 0;
  while (true)
  {
    char at = wordsearch[y * width + x];
    if (at != word[wordit])
      return false;

    if (wordit == word.Length - 1)
      return true;

    wordit++;

    x += xdir;
    y += ydir;

    if (x < 0 || y < 0 || x >= width || y >= height)
      return false;
  }
}

public int SearchCross(int x, int y)
{
  if (x == 0 || y == 0 || x == width - 1 || y == width - 1)
    return 0;

  char at = wordsearch[y * width + x];
  if (at != 'A')
    return 0;

  int found = 0;
  for (int ydir = -1; ydir <= 1; ++ydir)
    for (int xdir = -1; xdir <= 1; ++xdir)
    {
      if (xdir == 0 || ydir == 0)
        continue;

      if (wordsearch[(y + ydir) * width + (x + xdir)] != 'M')
        continue;
      if (wordsearch[(y - ydir) * width + (x - xdir)] != 'S')
        continue;

      found++;
    }

  if (found == 2)
    return 1;

  return 0;
}

[-] CameronDev@programming.dev 1 points 2 weeks ago

I haven't quite started yet, and this one does feel like a busy work kinda problem. I was wondering if I could write something to rotate the board and do the search, but I think that might be not worth the effort

this post was submitted on 04 Dec 2024
18 points (95.0% liked)

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