this post was submitted on 19 Apr 2025
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    Linux For Life (lemm.ee)
    submitted 2 weeks ago by azha@lemm.ee to c/linuxmemes@lemmy.world
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    [–] kewko@sh.itjust.works -2 points 2 weeks ago (1 children)

    If -t is specified -f is assumed and redundant, but also it will try to do graceful l, but with a patience of a cranky toddler

    [–] aeiou_ckr@lemmy.world 20 points 2 weeks ago (1 children)

    Not really. If -f (force) is removed windows will shutdown similar to pressing the shutdown button and will wait for your input regarding open programs. -f is needed to just just β€œdo it” with no hesitation or response from the user.

    [–] kewko@sh.itjust.works -2 points 2 weeks ago* (last edited 2 weeks ago) (2 children)

    Straight from the doc

    /t Sets the time-out period before shutdown to xxx seconds. The valid range is 0-315360000 (10 years), with a default of 30. If the timeout period is greater than 0, the /f parameter is implied.

    [–] Lupus@feddit.org 29 points 2 weeks ago (1 children)

    Sooo when you use the prompt

    Shutdown.exe -r -t 00

    You would need the -f since we defined the timeout period as 0. Because:

    If the timeout period is greater than 0, the /f parameter is implied.

    [–] kewko@sh.itjust.works 3 points 2 weeks ago (1 children)

    Yeah fair enough -f -s does the same thing as -t 0?

    [–] criticon@lemmy.ca 2 points 2 weeks ago

    I don't trust windows enough, I always input both parameters

    [–] aeiou_ckr@lemmy.world 1 points 2 weeks ago

    Ah nice. I have only used it with -t 0. I’m glad to have learn something today.