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submitted 11 months ago* (last edited 11 months ago) by andioop@programming.dev to c/programming_horror@programming.dev

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[-] recursive_recursion@programming.dev 9 points 11 months ago* (last edited 11 months ago)

modulo

pseudocode:

if number % 2 == 0
  return "number is even" (is_num_even = 1 or true)
else
  return "number is odd" (is_num_even = 0 or false)

plus you'd want an input validation beforehand

[-] mac@programming.dev 23 points 11 months ago* (last edited 11 months ago)

who needs modulo when you can get less characters out of

while (number > 1) {
  number -= 2;
}
return number;

very efficient

edit: or theres the trusty iseven api

[-] nullPointer@programming.dev 9 points 11 months ago

here is somewhat less:

return (number % 2) == 0;

[-] pivot_root@lemmy.world 10 points 11 months ago

return !(number & 1);

[-] venoft@lemmy.world 8 points 11 months ago* (last edited 11 months ago)

This is the way. Modulo takes too long to compute, bitwise compare should be a lot faster.

return !(number &amp; 0x1);

[-] recursive_recursion@programming.dev 5 points 11 months ago* (last edited 11 months ago)

oh shit yo

this comment chain is pretty awesome, I learned a lot from this thanks!

[-] huf@hexbear.net 4 points 11 months ago

just check the last bit jesus christ, what is it with these expensive modulo operations?!

return !(n&1);

[-] perviouslyiner@lemm.ee 2 points 11 months ago

are the negative numbers all even?

[-] I_am_10_squirrels@beehaw.org 2 points 11 months ago

Yes

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this post was submitted on 07 Dec 2023

190 points (90.9% liked)

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