this post was submitted on 05 Apr 2024
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In the lambda calculus, we can represent the identity function as
λx.x. To solve for N=NP, we can use this identity function to substituteNwithNPin the lambda calculus.First, let's define the identity function:
λx.xNow, we can use this function to substitute
NwithNP:λN.N(N) = λN.NPThis expression states that the function that takes
Nas input and returnsNPis equivalent to the identity functionλx.x.