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Kansas^-1 (sh.itjust.works)

submitted 7 months ago by sjmarf@sh.itjust.works to c/mathmemes@lemmy.blahaj.zone

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[-] onion@feddit.de 1 points 6 months ago

So one over Kansas times x not Kansas times one over x?

[-] Wilzax@lemmy.world 3 points 6 months ago* (last edited 6 months ago)

Kansas is a function name, not a variable in this notation. Otherwise it would be (Kansa/s)(x) which simplifies to (a^2) (k)(n)(x)

this post was submitted on 01 May 2024

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