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Day 1: Historian Hysteria

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[-] sjmulder@lemmy.sdf.org 3 points 2 weeks ago

Solution in C

Part 1 is a sort and a quick loop. Part 2 could be efficient with a lookup table but it was practically instant with a simple non-memoized scan so left it that way.

[-] mcmodknower@programming.dev 1 points 2 weeks ago* (last edited 2 weeks ago)

You are using some interesting techniques there. I never imaged you could use the result of == for adding to a counter.

But how did you handle duplicates in part 2?

[-] sjmulder@lemmy.sdf.org 1 points 2 weeks ago

Iโ€™m not sure if I understand the question correctly but for every number in the left array I count in the right array. That means duplicate work but shrug ๐Ÿ˜…

this post was submitted on 01 Dec 2024
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