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this post was submitted on 02 Dec 2024
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I will probably slow down and try to solve the problems on the weekends rather than daily. Anyway, 9:
part 1
This was straightforward in that all you need to do is implement the algorithm as given. I did optimise a little using the arithmetic progression sum, but this is a speed-up of, at most like, a factor of 9.I am pretty sure I did an OK job at avoiding edge cases, though I suspect this problem has many of them.
part 2
Again, the algorithm is more or less given: Start from the back, look for a hole that'll work, and put it in if you can. Otherwise, don't. Then, calculate the contribution to the checksum.The complex part was the "look for a hole" part. My input size was 19999, meaning an O(n^2^) solution was probably fast enough, but I decided to optimise and use a min heap for each space size prematurely. I foresaw that you need to split up a space if it is oversized for a particular piece of data, i.e. pop the slot from the heap, reduce the size of the slot, and put it in the heap corresponding to the new size.