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A Linear Algebra Trick for Computing Fibonacci Numbers Fast
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It's not that hard to check yourself. Running the following code on my machine, I get that the linear algebra algorithm is already faster than the naive algorithm at around n = 100 or so. I've written a more optimised version of the naive algorithm, which is beaten somewhere between n = 200 and n = 500.
Try running this Python code on your machine and see what you get:
Here's what it prints on my machine:
Nice.
I have successfully stuck my foot in my own mouth.