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submitted 7 months ago by Fuctangle@sh.itjust.works to c/196@lemmy.blahaj.zone

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[-] quantenzitrone@feddit.de 7 points 7 months ago

since gender is not binary, trans is not a binary operation

so double trans [ interpreted as trans²: x ↦ trans(trans(x)) ] is not necessarily the identity funcion [ id: x↦x ]

[-] Fuctangle@sh.itjust.works 4 points 7 months ago

Any gender is necessarily an identity function, checkmate (I'm not numerate)

this post was submitted on 13 Apr 2024

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