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Player calculus (lemmy.world)
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[-] v4ld1z@lemmy.zip 74 points 1 month ago

My mind was going in a different direction

[-] FenrirIII@lemmy.world 10 points 1 month ago

I, too, visualized a giant game of Twister

[-] ArbitraryValue@sh.itjust.works 4 points 1 month ago

The "wear a loincloth before growing 30 feet tall" direction?

[-] smeg@feddit.uk 51 points 1 month ago

Who needs friends? A level 3 duergar rune knight can use giant's might and enlarge person to become huge in one turn, and then action surge to get wrestling right away!

[-] smeg@feddit.uk 21 points 1 month ago

(Also at level 18 you can become even larger)

[-] EonNShadow@pawb.social 11 points 1 month ago

That would imply that Lluis Abadias would play anything not reptilian

And if you know of them, that simply won't do

[-] smeg@feddit.uk 8 points 1 month ago

I don't, but whoever they are I look down on them from atop a giant dwarf

[-] NakariLexfortaine@lemm.ee 33 points 1 month ago

And this is how "Scroll of Instant Kaiju" began.

[-] BallsandBayonets 32 points 1 month ago

But you only deal 2d4 extra damage. I think, if you can grow your hands to the size of horses, you should deal just a bit more damage.

[-] WolfLink@sh.itjust.works 17 points 1 month ago

Doubling the size in each dimension should at least double the damage

[-] BallsandBayonets 6 points 1 month ago

My (very briefly) Gargantuan Wild Shaped Dire Wolf salivates at this thought.

[-] Tiempo@ttrpg.network 3 points 1 month ago

Math time!!!!

Lets say we have a Dragon born with Volume=v (v=xyz), Mass=m. It's Density would be d=m/v. We also know that it kick ass with a Force=F, where F=m*a, being a the acceleration of it's arms while punching.

If our DB double it's size in every dimension, it means that it's Volume is: V'=2x2y2z > V'=8(xyz) > V'=8V.

If we assume it's density keeps constant, then it means it gains some mass.

D=m/v, but now D=m'/v' so

m/v=m'/v' , mv=m/(8v) , m8v/v=m' , m'=8m

If we assume that it will punch with the same acceleration as always, F=m*a

F'=m'a, F'=8ma F'=8(m*a) F'=8F

So, changing from medium to large would imply changing 8 times the strength. If this keeps up for every step, then we are talking about one extra change to get to huge, and then one to get to gargantuan . So 8^3 times the force. And if we assume a linear relation between force and damage, 8^3 times the damage...

Yeah... A few extra d4s seems.... Meh

[-] Archpawn@lemmy.world 5 points 1 month ago

I was thinking it was a grapple thing, but Huge is already big enough to grapple anything.

[-] ArbitraryValue@sh.itjust.works 1 points 1 month ago* (last edited 1 month ago)

I think if you're just Huge and you're grappling a Gargantuan dragon, you're going to look like a dog humping his leg. Which may be what OP wants to do, but still...

this post was submitted on 18 Sep 2024
267 points (98.2% liked)

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