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[-] Localhorst86@feddit.de 43 points 9 months ago

x + 2 = x - 2

I found x, twice even. EZ

[-] 0x4E4F@sh.itjust.works 13 points 9 months ago

That is probably the most correct answer.

[-] urist@lemmy.blahaj.zone 28 points 9 months ago

I find this meme and this comment section distressing. Y’all are bad at basic algebra.

Carry on, I guess.

[-] 0x4E4F@sh.itjust.works 2 points 9 months ago
[-] WatTyler@lemmy.zip 28 points 9 months ago

Subtract x from both sides of the equation. You get 2 = -2 which is incorrect and nonsensical.

[-] 0x4E4F@sh.itjust.works 5 points 9 months ago* (last edited 9 months ago)

I know that, but @Urist@lemmy.blahaj.zone said that most of us here are bad at basic algebra. Not that I'm great at it (I had an 8 average in all 4 maths in uni), but I do believe that most of us here were correct. This is unsolvable using classic algebra.

[-] urist@lemmy.blahaj.zone 7 points 9 months ago

Just to be clear: the comment was meant in a lighthearted way and not meant to be taken personally, especially toward those who are confident with their math skills.

My bad.

[-] 0x4E4F@sh.itjust.works 2 points 9 months ago

Apology accepted 😊.

To be honest, my comment was meant to have double meaning. On one hand, I was certain that this thing can't be solved with classic algebra. On the other, it's been a while since I've done any math with pen and paper, so I figured "I might have forgotten something that could make this solvable". In either case, I was curious 😂.

[-] pruwybn@discuss.tchncs.de 23 points 9 months ago

2 = -2, easy

[-] BoxerDevil@lemmy.world 16 points 9 months ago

Can someone smart explain it to dumb me

[-] odium@programming.dev 73 points 9 months ago* (last edited 9 months ago)

Explanation: How did they get from

x + 2 = x - 2

to

(x+2)(x-2)=0?

That's not a valid step.

[-] 520@kbin.social 18 points 9 months ago* (last edited 9 months ago)

To further clarify,

(x+2)(x-2) means to take the result of X+2 and times it with the result of x-2.

While it is common in algebra to bring the other side over, in order to simplify it, this isn't how you'd do it.

Here, you'd either cancel out the X (by removing it on both sides) or the -2 (by adding 2 to both sides) over to make 2=-2 or X+4=X respectively, which are both nonsense equations.

[-] pendingdeletion@lemmy.world 6 points 9 months ago

and times it with the result

and multiply it with the result

[-] 520@kbin.social 4 points 9 months ago* (last edited 9 months ago)
[-] pendingdeletion@lemmy.world 2 points 9 months ago

Not really, no… “times” is not a verb. You can multiply 2 by 2, and you can express that as “2 times 2”, but it is not correct to “times 2 by 2”.

[-] 520@kbin.social 3 points 9 months ago
[-] pendingdeletion@lemmy.world 2 points 9 months ago

Not sure what you think the relevance of a Spanish-English translation of the word “multiplying” has here… but nonetheless, you can see the correct usage of the word “multiply” versus the word “times” in my explanation above. For further clarification I would suggest a real dictionary, like Oxford, Meriam-Webster, etc.

I’m sure plenty of people will continue to make the mistake and it will become an accepted variant, though I wouldn’t consider it to be the correct usage of the word. Similar to the word “irregardless”, it’s a word, it’s used incorrectly in place of “regardless” very often, and therefore is an accepted variant. It’s just not the correct word to use. This is why I offered you my initial correction.

[-] 520@kbin.social 2 points 9 months ago* (last edited 9 months ago)

Not sure what you think the relevance of a Spanish-English translation of the word “multiplying” has here

It's a more authoritative answer than a random comment by a grammar nazi.

Also the dictionaries you mentioned aren't great about including common informal language, which is what 'times by' is.

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[-] janet_catcus@lemmy.blahaj.zone 2 points 9 months ago* (last edited 9 months ago)

they start off with S' though... looks like they pretended to try to derive?

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[-] 0x4E4F@sh.itjust.works 31 points 9 months ago

Almost everything is wrong in his answer.

The correct answer is, it's unsolvable.

X + 2 = X - 2

X - X = - 2 - 2

0 = - 4

[-] olsonexi@lemmy.wtf 17 points 9 months ago

The real correct answer is that it only works mod 4

[-] SpaceNoodle@lemmy.world 9 points 9 months ago

Only the first step is wrong.

[-] 0x4E4F@sh.itjust.works 3 points 9 months ago* (last edited 9 months ago)

Yeah, my bad 👍.

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[-] PM_Your_Nudes_Please@lemmy.world 20 points 9 months ago* (last edited 9 months ago)

It’s not solvable using traditional algebra.

Typically you would try to get all of the variables on one side, and all of the numbers on the other.

So in this instance, you’d start by moving them around to get things together:
x+2 = x-2
x+2-x = -2
x-x = -2-2

But then you simplify, and cancel out any variables that need to be cancelled. In this case we see “x-x” so that cancels out to 0. And we see -2-2 which simplifies into -4. So the end result is:

0=-4

Which is obviously a nonsense answer. In the original post, homeslice did the first step wrong, moved everything over to the left incorrectly, (inadvertently setting the whole equation equal to 0) and the whole thing was downhill from there; Since the first step of their solution was wrong, everything behind it was also wrong.

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[-] DerisionConsulting@lemmy.ca 7 points 9 months ago

There isn't a valid answer to the question.

Ignore the numbers, and just think about this:
Is there a number that you can add 2 to, that would equal the same about as if you subtracted 2 from it?
The answer is no.

So the person, who is pretending to be smart, just did a bunch of fake math.
Also √4 = 2, so the "answer" they have is just them trying to re-write the question x + 2 = x - 2.

[-] 0x4E4F@sh.itjust.works 3 points 9 months ago
[-] rasensprenger@feddit.de 3 points 9 months ago* (last edited 9 months ago)

The square root of x is usually defined as the positive real number that squares to x, so x^2 = 4 => x = +-2 but sqrt(4) = 2, not +-2

The complex sqrt function is multivalued, but that opens a whole other can of worms

[-] digdug@kbin.social 6 points 9 months ago

And even if you allowed sqrt(4) = ±2, it would still be invalid to evaluate it to -2 on one side of the equation, but then use +2 on the other side.

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[-] 0x4E4F@sh.itjust.works 2 points 9 months ago* (last edited 9 months ago)

Oh yeah, you're right, now I remembered 🤦. Been a while 😂, almost 20 years.

[-] BradleyUffner@lemmy.world 13 points 9 months ago* (last edited 9 months ago)

Right there:

[-] joranvar@feddit.nl 9 points 9 months ago* (last edited 9 months ago)

Would it be a rabbit hole to try and find any merit in this solution when interpreting it as: "if x is in a superposition of 2 and -2, the x + 2 = x - 2 would be true in 1/4 of the observations", or something like that?

It is the closest thing to a "solution" that I can imagine, but doesn't fit any laws that I know of or understand, and would probably break down on any scrutiny, but it feels like something is there.

[-] urist@lemmy.blahaj.zone 7 points 9 months ago* (last edited 9 months ago)

x cant be both values at the same time, not under what most people consider to be math. Feel free to write your own logical system and see where that takes you, though.

I think the only “solution” that works is addition/subtraction under mod 4 (or mod 2 I suppose) like another poster suggested. Then we’d have:

X + 2 = x - 2

X + 4 = x (Add 2 to both sides)

X + 0 = x (4 = 0 mod 4)

X = x (True for all x)

[-] 0x4E4F@sh.itjust.works 3 points 9 months ago* (last edited 9 months ago)

(True for all x)

But not true for any rational number if you try it in the equation.

Thus, this is not a solution. The equation is unsolvable with rational numbers.

[-] urist@lemmy.blahaj.zone 5 points 9 months ago* (last edited 9 months ago)

Correct, not solvable with rational numbers. I should have been more clear. When we’re doing arithmetic modulo x, it’s assumed to be with integers.

To be clear, this is a solution only in Z_4 which is not what most people mean when they’re look for answers to algebra problems. And it would be a solution for all x in Z_4 (which are integers, see this page that I assume is a good summary)

edit: this page might be better

[-] 0x4E4F@sh.itjust.works 3 points 9 months ago

Yes, that is correct, this is solvable in modular algebra... but, in that case, the tripple horizontal line equal sign should have been used, not the double horizontal line one, which of course indicates classic algebra.

[-] urist@lemmy.blahaj.zone 2 points 9 months ago

Also true but I’m not sure how to do that on my phone so I gave up

Maybe lemmy can do mathjax someday

[-] 0x4E4F@sh.itjust.works 2 points 9 months ago

I was talking about the person that posted the equation. They should have found a way if they wanted this thing solved, lol 😂.

[-] 0x4E4F@sh.itjust.works 6 points 9 months ago

Don't overthink it, it's made to be unsolvable on purpose, just to test how much math your average Joe knows.

[-] joranvar@feddit.nl 4 points 9 months ago

Haha I got that :) @Urist@lemmy.blahaj.zone is right, I was halfheartedly looking for a logic system in which it could make sense. Still, I would have major issues with the first step as it is shown, but I am wondering about systems where, say, each x <- {..}, then what would be the set, and the probability of the correct solution.

Something I need to be more awake for, and it may be easier to solve without resorting to powers and roots, haha.

[-] joranvar@feddit.nl 4 points 9 months ago

Reply to self: really not that useful. That would be the same as just throwing all variables/coordinates of the solution in a set, forgetting their names and then filling them back in as some kind of madlibs experiment. And multiple solutions don't grow with the exponent on x, that is just an odd/even thing. Don't know shat I was thinking...

[-] 0x4E4F@sh.itjust.works 2 points 9 months ago

I can tell you one thing, the equation makes perfect sense if x --> inf.

[-] dtjones@lemmy.world 9 points 9 months ago

I know we're supposed to assume x is a real number, but this could be true if x is a sinusoidal waveform with period = 4. The question didn't specify the range or what set of numbers on which x is defined.

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[-] BartyDeCanter@lemmy.sdf.org 6 points 9 months ago

Clearly X= |2> + |-2> 😅

[-] itslilith@lemmy.blahaj.zone 4 points 9 months ago

⬆️ this poster didn't normalize their linear combination of wave functions

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this post was submitted on 22 Jan 2024
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Math Memes

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