for example?
reksas
its just facade finally falling and revealing the rot
anyone can do whatever on their own, but if it affects anyone else than that one person its not just that one person's business. I cant see the insistence of using imperial system as anything else than america has used it in the past, and therefore its american system and because america is the best it must be the best system to use and to claim anything else is to hate america.
it has come to the point that i might consider even chinese controlled stuff over google, though i would prefer european software. I'm just so sick and tired of all this bullshit.
as long as google doesnt control it, its good enough for me
not sure how these are, but i'm planning on getting one at some point. These should have some other os called murena, which is close to android but not quite, according to the website.
whataboutism
jos tietäisi mistä noita ostaa, voisi ostaa useamman ja laittaa jonkun kivan linux distron ja koittaa myydä niitä uudelleen
https://www.techradar.com/phones/android/google-will-soon-stop-you-sideloading-unverified-apps-heres-what-that-means-for-you tuo oli äkkiseltään kelvollisen oloinen uutinen aiheesta. Eli kehittäjien pitää jakaa henkilötietonsa googlelle että porukka saa asentaa, vaikka eivät käyttäisi play kauppaa. Eli google voi täysin vapaasti estää minkä tahansa ohjelman ja ottaa käyttäjilta oikeuden tehdä omalla laitteellaan mitä haluaa.
Eihän tuo periaatteessa lukitse sitä pelkkään play kauppaan, mutta käytännössä se tekee saman asian. Jos se ohjelman asentaminen on googlen armon alainen vaikka sitä ei asentaisi sieltä sovelluskaupasta, miten se eroaa siitä että se olisi siellä?
muuten kiva, mutta ainakin omassa fairphonessa on googlen ohjelmat, android ja joku ihme "unknown" ohjelma joka näkyy palomuurissa, mutta se näyttää olevan joku googlen juttu jonka olen näemmä "poistanut". Itsellä on tosin aiempi malli.
Jos tuossa on oikeasti joku muu kuin android niin ostan kyllä heti, google on viheliäisintä paskaa mitä löytyy, ehkä jopa microsoftiakin pahempi. Ne alkaa nyt estämään ohjelmien vapaan asentamisen, eli androidista tulee varmaan suljetumpi käyttöjärjestelmä kuin Ipuhelimista, kun ottaa huomioon että ne laitettiin sallimaan muutakin kuin niiden oma sovelluskauppa. Eli ainoastaan googlen niin mahdottoman turvallisesta sovelluskaupasta saat asentaa mitään, paitsi jos google suuressa armossaan hyväksyy jonkun kehittäjän erikseen.
Olisi kyllä tosi tervetullut pelastus tuo, kun on kuumottanut tuo googlen temppu. Käytän itse melkein pelkästään f-droidista laitettuja ohjelmia.
i had my linkedin profile suspended in case i ever needed it for something. now i had it closed instead, though not before deleting any worthwhile information on it, not that i believe they will actually delete my information despite whatever they claim.
i'd say its still easier to just choose desired level of precision with 3.333333333 than deal with imperial's conversion maddness, even if you can divide them evenly. I guess imperial is ok if you dont ever have to use it with any other system, but lack of combitability is quite isolationist.
With imperial, every unit is like it's own singular instance where in metric each unit is part of the system. Trying to convert between them seems like a nightmare (i dont want to even try, but i assume those who use imperial just have to.)
Like, how many inches are on 1000 miles? Try to convert that exactly in your head without using calculator or paper and within 10 seconds. How many square feet are on 37 acres? How much does 5,5 gallons of water weigh in stones?
Or lets say we have container with measurements of 3x3x3 inches (i'll be merciful and use same unit for each dimension) MysteryLiquid™ (use calculator for this one if you try to calculate it) with density of 3,337 pounds / ...perch..? or more commonly 0,00625 acres (not many area units in imperial). How much does the MysteryLiquid™ in the container weigh in stones?
In metric the density would be about 301 kg/m3.
3 inches is 0.0762 metres so container would be 0.0762^3^ which is 0,000442450728m3 which is 442.450728 cm³
So m =p x V = 301kg x 0.000442m3 = 0.133kg, try calculating that whole thing in imperial, using crazy different units without ripping out your hair. I used sensible units for metric in this one, but i could have used nanograms, mm^3^ and decimeters instead and it would just mildly inconvenience me when calculating, and also produce way bigger numbers but at least the conversion factors would remain same.
Not being able to divide some measurements in even numbers is very small price to pay for being able to calculate things more easily.