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Evil Ones (lemmy.world)
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[-] pooberbee@lemmy.ml 1 points 1 day ago

Yeah, you would get a runtime error calling that member without checking that it exists.

[-] masterspace@lemmy.ca 1 points 13 hours ago* (last edited 13 hours ago)

Because that object is of a type where that member may or may not exist. That is literally the exact same behaviour as Java or C#.

If I cast or type check it to make sure it's of type Bar rather than checking for the member explicitly it still works:

And when I cast it to Foo it throws a compile time error, not a runtime error:

this post was submitted on 20 Dec 2024
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