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[-] cadekat@pawb.social 8 points 3 months ago* (last edited 3 months ago)

This looks like O(n), because you don't include constants when calculating Big-O. It's still ~26 times slower than the implementation without the inner loop.

~~This looks like O(n^2) because of the sub.~~

I was right the first time. sub is "substring" and not "substitute".

this post was submitted on 22 Jul 2024
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