this post was submitted on 24 Jul 2024
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Science Memes

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A place for majestic STEMLORD peacocking, as well as memes about the realities of working in a lab.



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[–] pr06lefs@lemmy.ml 174 points 1 year ago* (last edited 1 year ago) (7 children)

What about plain old x = -10?

-10 ^ 2 = 100
-10 ^ 3 = -1000
-10 ^ 5 = -100000

[–] Redacted@lemmy.world 122 points 1 year ago

Isn't that the joke?

[–] Enkers@sh.itjust.works 68 points 1 year ago (1 children)

That's what he wrote, I imagine.

[–] Siethron@lemmy.world 39 points 1 year ago (1 children)

It is, but with imaginary numbets

[–] JackbyDev@programming.dev 47 points 1 year ago

i² = -1 so...

[–] dwindling7373@feddit.it 27 points 1 year ago

10 * i^2 is -10.

[–] thedudeabides@lemmy.dbzer0.com 17 points 1 year ago (1 children)
[–] pr06lefs@lemmy.ml 35 points 1 year ago (1 children)

people being pedantic showoffs doesn't really register as humor for me, TBH

[–] thedudeabides@lemmy.dbzer0.com 13 points 1 year ago

That's true, the OOP is being quite snarky with their comment on a post where someone's had a genuine basic doubt

[–] Deconceptualist@lemm.ee 9 points 1 year ago

That was my immediate thought too.

[–] Sphks@lemmy.dbzer0.com 4 points 1 year ago
[–] Deebster@programming.dev 102 points 1 year ago (2 children)

When all you have is an imaginary hammer, everything looks like a rotation around the imaginary unit circle.

Explanation of mathsx = -10, i = √-1 so i² = -1 and 10i²=-10

[–] MonkderVierte@lemmy.ml 15 points 1 year ago (1 children)

Found the math but no explanation.

[–] JackbyDev@programming.dev 15 points 1 year ago (11 children)

The squareroot of 100 is ±10.

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[–] fx3@beehaw.org 4 points 1 year ago (1 children)

IIRC, your spoilery “so” is the other way round. The right side is the definition, and the left-hand side a layman’s shorthand, as the root operator isn’t defined on negative numbers.

I might very well be wrong. My being a mathematician has been over for a while now, my being a pedantic PITA not though.

[–] Deebster@programming.dev 5 points 1 year ago

I don't know enough to know how correct your pedantry is (technically or not), but to explain the meme it made sense to go through the symbols in the order you see them. I never got any points from the proof questions in exams anyway.

[–] NigelFrobisher@aussie.zone 37 points 1 year ago (1 children)

Wait, isn’t x just -10 if x^3 is not 1000?

[–] bi_tux@lemmy.world 15 points 1 year ago
[–] iAvicenna@lemmy.world 27 points 1 year ago

that is a very long way to write -10

[–] southsamurai@sh.itjust.works 13 points 1 year ago (2 children)
[–] Cryophilia@lemmy.world 45 points 1 year ago (1 children)

That's because the explanation was about 10 times as complicated as it needs to be

[–] olafurp@lemmy.world 12 points 1 year ago (1 children)
[–] mexicancartel@lemmy.dbzer0.com 23 points 1 year ago

He is trolling with overcomplicating

[–] Yaysuz@lemm.ee 10 points 1 year ago (2 children)

What an extremely unnecessary explanation. As a math teacher I would have deducted points for this answer.

[–] androogee@midwest.social 8 points 1 year ago

"show your work"

Malicious compliance intensifies

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[–] Ravi@feddit.org 9 points 1 year ago (1 children)

No definition what values are suitable for x.

[–] quicksand@lemm.ee 21 points 1 year ago (4 children)

x has to be -10, right? Or am I missing something?

[–] jacksilver@lemmy.world 7 points 1 year ago (2 children)

Yeah, I think the point is that the person answering was wrong/over complicating. If x=10i, then x^2 would be -100 (or potentially -10 depending on what you think the ^2 is applied to).

[–] Khanzarate@lemmy.world 23 points 1 year ago

They said x=10i^2, not 10i. Difference is it equals -10, and they chose not to simplify.

They're correct, it's just overcomplicated as fuck in ways that are correct but completely irrelevant to the question.

[–] WolfLink@sh.itjust.works 4 points 1 year ago

The answer in the meme (10i^2) is -10

[–] Ravi@feddit.org 4 points 1 year ago

Depends on what are the allowed values for x are. Real numbers, complexe numbers, binary or I made up my own numbers ;)

[–] Malgas@beehaw.org 3 points 1 year ago (1 children)

Probably what they were going for, but there are literally an infinite number of exotic arithmetic spaces you could ask this question in. For example, x=10 works in any ring with a modulus greater than 100 and less than 1000.

[–] Umbrias@beehaw.org 1 points 1 year ago

fortunately math problems are administered in the context of the class, so it will be pretty obvious that it's in the complex plane.

[–] Xavienth@lemmygrad.ml 5 points 1 year ago* (last edited 1 year ago) (1 children)

Therefore i¹⁰ = ln(-1)¹⁰/pi¹⁰ = -1

This is true but does not follow from the preceding steps, specifically finding it to be equal to -1. You can obviously find it from i²=-1 but they didn't show that. I think they tried to equivocate this expression with the answer for e^iπ^ which you can't do, it doesn't follow because e^iπ^ and i¹⁰ = ln(-1)¹⁰/pi¹⁰ are different expressions and without external proof, could have different values.

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