Haskell

Plenty of scope for making part 2 faster, but I think simple is best here. Forgot to sort the lists in the first part, which pushed me waaay off the leaderboard.

import Data.List

main = do
  [as, bs] <- transpose . map (map read . words) . lines <$> readFile "input01"
  print . sum $ map abs $ zipWith (-) (sort as) (sort bs)
  print . sum $ map (\a -> a * length (filter (== a) bs)) as

Uiua

For entertainment purposes only, I'll be trying a solution in Uiua each day until it all gets too much for me...

$ 3   4
$ 4   3
$ 2   5
$ 1   3
$ 3   9
$ 3   3
⊜∘⊸≠@\n     # Partition at \n.
⊜(⍆∵⋕)⊸≠@\s # Partition at space, parse ints, sort.

&p/+/(⌵-). # Part1 : Get abs differences, sum, print.

&p/+×⟜(/+⍉≡⌕)°⊂ # Part 2 : Count instances, mul out, sum, print.

TypeScript

import { AdventOfCodeSolutionFunction } from "./solutions";

function InstancesOf(sorted_array: Array<number>, value: number) {
    const index = sorted_array.indexOf(value);
    if(index == -1)
        return 0;

    let sum = 1;

    for (let array_index = index + 1; array_index < sorted_array.length; array_index++) {
        if(sorted_array[array_index] != value)
            break;

        sum += 1;
    }

    return sum;
}

export const solution_1: AdventOfCodeSolutionFunction = (input) => {
    const left: Array<number> = [];
    const right: Array<number> = [];

    const lines = input.split("\n");

    for (let index = 0; index < lines.length; index++) {
        const element = lines[index].trim();
        if(!element)
            continue;

        const leftRight = element.split("   ");
        left.push(Number(leftRight[0]));
        right.push(Number(leftRight[1]));
    }

    const numSort = (a: number, b: number) => a - b;
    left.sort(numSort);
    right.sort(numSort);

    let sum = 0;
    for (let index = 0; index < left.length; index++) {
        const leftValue = left[index];
        const rightValue = right[index];

        sum += Math.abs(leftValue - rightValue);
    }

    const part1 = `Part 1: ${sum}`;

    sum = 0;
    for (let index = 0; index < left.length; index++) {
        sum += left[index] * InstancesOf(right, left[index]);
    }

    const part2 = `Part 2: ${sum}`;

    return `${part1}\n${part2}`;
};

Nim

I've got my first sub-1000 rank today (998 for part 2). Yay!
Simple and straightforward challenge, very fitting for 1st day. Gonna enjoy it while it lasts.

proc solve(input: string): AOCSolution[int, int] =
  var l1,l2: seq[int]
  for line in input.splitLines():
    let pair = line.splitWhitespace()
    l1.add parseInt(pair[0])
    l2.add parseInt(pair[1])
  l1.sort()
  l2.sort()

  block p1:
    for i in 0..l1.high:
      result.part1 += abs(l1[i] - l2[i])

  block p2:
    for n in l1:
      result.part2 += n * l2.count(n)

Codeberg repo

Rust

Right IDs are directly read into a hash map counter.

use std::str::FromStr;
use std::collections::HashMap;

fn part1(input: String) {
    let mut left = Vec::new();
    let mut right = Vec::new();
    for line in input.lines() {
        let mut parts = line.split_whitespace()
            .map(|p| u32::from_str(p).unwrap());
        left.push(parts.next().unwrap());
        right.push(parts.next().unwrap());
    }
    left.sort_unstable();
    right.sort_unstable();
    let diff: u32 = left.iter().zip(right)
        .map(|(l, r)| l.abs_diff(r))
        .sum();
    println!("{diff}");
}

fn part2(input: String) {
    let mut left = Vec::new();
    let mut right: HashMap<u32, u32> = HashMap::new();
    for line in input.lines() {
        let mut parts = line.split_whitespace()
            .map(|p| u32::from_str(p).unwrap());
        left.push(parts.next().unwrap());
        *right.entry(parts.next().unwrap()).or_default() += 1;
    }
    let similar: u32 = left.iter()
        .map(|n| n * right.get(n).copied().unwrap_or_default())
        .sum();
    println!("{similar}");
}

util::aoc_main!();

Smalltalk

day1p12: input    
	| list1 list2 nums dist sim |
	
	list1 := OrderedCollection new.
	list2 := OrderedCollection new.
	
	input linesDo: [ :l |
		nums := l substrings collect: [ :n | n asInteger ].
		list1 add: (nums at: 1).
		list2 add: (nums at: 2).
	].

	list1 sort.
	list2 sort.
	
	dist := 0.
	list1 with: list2 do: [ :a :b | dist := dist + (a - b) abs ].
	
	sim := list1 sumNumbers: [ :x | x * (list2 occurrencesOf: x) ].
	
	^ Array with: dist with: sim.

I’m quite inexperienced as a programmer, I learned most of the basic concepts from playing human resource machine and 7 billion humans. After mucking about writing some CLI utilities in Perl and python, I’ve decided to give rust a go.

Part 1

Part 2

Python

left_list = []
right_list = []

for line in file:
    split_line = line.split()
    left_list.append(int(split_line[0]))
    right_list.append(int(split_line[1]))

sorted_left = sorted(left_list)
sorted_right = sorted(right_list)
distance = []
for left, right in zip(sorted_left, sorted_right):
    distance.append(abs(left - right))

total = sum(distance)

print(total)

file = open('input.txt', 'r')
left_list = []
right_list = []

for line in file:
    split_line = line.split()
    left_list.append(int(split_line[0]))
    right_list.append(int(split_line[1]))

sim_score = 0
for item in left_list:
    sim = right_list.count(item)
    sim_score += (sim * item)

print(sim_score)

I am sure there were better ways to do this, this was just the first way in my head, in the order it appeared

Solution in C

Part 1 is a sort and a quick loop. Part 2 could be efficient with a lookup table but it was practically instant with a simple non-memoized scan so left it that way.

C#

public class Day01 : Solver
{
  private ImmutableArray<int> left;
  private ImmutableArray<int> right;

  public void Presolve(string input)
  {
    var pairs = input.Trim().Split("\n").Select(line => Regex.Split(line, @"\s+"));
    left = pairs.Select(item => int.Parse(item[0])).ToImmutableArray();
    right = pairs.Select(item => int.Parse(item[1])).ToImmutableArray();
  }

  public string SolveFirst() => left.Sort().Zip(right.Sort()).Select((pair) => int.Abs(pair.First - pair.Second)).Sum().ToString();

  public string SolveSecond() => left.Select((number) => number * right.Where(v => v == number).Count()).Sum().ToString();
}

Not going to push hard on these first days (fever being a reason), so I slept in quite a bit before looking at the problem.

List<int> _LeftList = new List<int>();
List<int> _RightList = new List<int>();

// Fed via File.ReadLines(...).Select(l => l.Trim())
public void Input(IEnumerable<string> lines)
{
  foreach (var line in lines)
  {
    var split = line.Split(' ', StringSplitOptions.RemoveEmptyEntries).Select(s => int.Parse(s));
    _LeftList.Add(split.First());
    _RightList.Add(split.Last());
  }
}

public void Part1()
{
  Console.WriteLine($"Sum: {_LeftList.Order().Zip(_RightList.Order()).Select(v => Math.Abs(v.First - v.Second)).Sum()}");
}
public void Part2()
{
  Console.WriteLine($"Sum: {_LeftList.Select(l => _RightList.Where(i => i == l).Count() * l).Sum()}");
}

Kotlin

No 💜 for Kotlin here?

import kotlin.math.abs

fun part1(input: String): Int {
    val diffs: MutableList<Int> = mutableListOf()
    val pair = parse(input)
    pair.first.sort()
    pair.second.sort()
    pair.first.forEachIndexed { idx, num ->
        diffs.add(abs(num - pair.second[idx]))
    }
    return diffs.sum()
}

fun part2(input: String): Int {
    val pair = parse(input)
    val frequencies = pair.second.groupingBy { it }.eachCount()
    var score = 0
    pair.first.forEach { num ->
        score += num * frequencies.getOrDefault(num, 0)
    }
    return score
}

private fun parse(input: String): Pair<MutableList<Int>, MutableList<Int>> {
    val left: MutableList<Int> = mutableListOf()
    val right: MutableList<Int> = mutableListOf()
    input.lines().forEach { line ->
        if (line.isNotBlank()) {
            val parts = line.split("\\s+".toRegex())
            left.add(parts[0].toInt())
            right.add(parts[1].toInt())
        }
    }
    return left to right
}

Go

package main

import (
	"bufio"
	"fmt"
	"os"
	"sort"
	"strconv"
	"strings"
)

func main() {
	input, _ := os.Open("input.txt")
	defer input.Close()

	left, right := []int{}, []int{}

	scanner := bufio.NewScanner(input)
	for scanner.Scan() {
		line := scanner.Text()
		splitline := strings.Split(line, "   ")
		l, _ := strconv.Atoi(splitline[0])
		r, _ := strconv.Atoi(splitline[1])
		left, right = append(left, l), append(right, r)
	}

	fmt.Printf("part 1 - total diff: %d\n", part1(left, right))
	fmt.Printf("part 2 - new total: %d\n", part2(left, right))
}

func part1(left, right []int) int {
	diff := 0
	sort.Ints(left)
	sort.Ints(right)

	for i, l := range left {
		if l > right[i] {
			diff += (l - right[i])
		} else {
			diff += (right[i] - l)
		}
	}
	return diff
}

func part2(left, right []int) int {
	newTotal := 0

	for _, l := range left {
		matches := 0
		for _, r := range right {
			if l == r {
				matches++
			}
		}
		newTotal += l * matches
	}
	return newTotal
}

Rust

I'm doing it in Rust again this year. I stopped keeping up with it after day 3 last year, so let's hope I last longer this time around.

use std::collections::HashMap;

use crate::utils::read_lines;

pub fn solution1() {
    let (mut id_list1, mut id_list2) = get_id_lists();

    id_list1.sort();
    id_list2.sort();

    let total_distance = id_list1
        .into_iter()
        .zip(id_list2)
        .map(|(left, right)| (left - right).abs())
        .sum::<i32>();

    println!("Total distance = {total_distance}");
}

pub fn solution2() {
    let (id_list1, id_list2) = get_id_lists();

    let id_count_map = id_list2
        .into_iter()
        .fold(HashMap::<_, i32>::new(), |mut map, id| {
            *map.entry(id).or_default() += 1i32;

            map
        });

    let similarity_score = id_list1
        .into_iter()
        .map(|id| id * id_count_map.get(&id).copied().unwrap_or_default())
        .sum::<i32>();

    println!("Similarity score = {similarity_score}");
}

fn get_id_lists() -> (Vec<i32>, Vec<i32>) {
    read_lines("src/day1/input.txt")
        .map(|line| {
            let mut ids = line.split_whitespace().map(|id| {
                id.parse::<i32>()
                    .expect("Ids from input must be valid integers")
            });

            (
                ids.next().expect("First Id on line must be present"),
                ids.next().expect("Second Id on line must be present"),
            )
        })
        .unzip()
}

I'm keeping my solutions up on GitHub.

Solution in ruby

This is my third program in ruby after the ruby tutorial and half of the rails tutorial, so don't expect anything too good from it.

Also i did this today since i had time, i will probably not comment every day.

I'm late to the party, as usual. Damned timezones. This year I'm going to tackle with a small handful of languages, but primarily Elixir and Gleam. This is my first time trying this languages in earnest, so expect some terrible, inefficient and totally unidiomatic code!
Here's day one:

Elixir

part_one =
  File.read!("input.in")
  |> String.split("\n", trim: true)
  |> Enum.map(fn line ->
    line
    |> String.split()
    |> Enum.map(&String.to_integer/1)
  end)
  |> Enum.reduce({[], []}, fn [first, second], {list1, list2} ->
    {[first | list1], [second | list2]}
  end)
  |> then(fn {list1, list2} ->
    {Enum.sort(list1), Enum.sort(list2)}
  end)
  |> then(fn {list1, list2} ->
    Enum.zip(list1, list2)
    |> Enum.map(fn {x, y} -> abs(x - y) end)
  end)
  |> Enum.sum()

part_two =
  File.read!("input.in")
  |> String.split("\n", trim: true)
  |> Enum.map(fn line ->
    line
    |> String.split()
    |> Enum.map(&String.to_integer/1)
  end)
  |> Enum.reduce({[], []}, fn [first, second], {list1, list2} ->
    {[first | list1], [second | list2]}
  end)
  |> then(fn {list1, list2} ->
    Enum.map(list1, fn line ->
      line * Enum.count(list2, fn x -> x === line end)
    end)
    |> Enum.sum()
  end)

IO.inspect(part_one)
IO.inspect(part_two)

Viml

I think viml is a very fun language, i like weird languages lol, so this year im doing it in viml while trying to use as many of the original ed/ex commands as i can (:d, :p, :a, :g, ...)

!cp ./puzzle1 ./puzzle1.editing
e ./puzzle1.editing

1,$sort
let row1 = []

g/^\d/let row1 = add(row1, str2nr(expand("<cword>"))) | norm 0dw
1d
1,$sort
g/^\d/execute 'norm cc' .. string(abs(expand("<cword>") - row1[line('.') - 1]))

$a|---ANSWER---
0
.
1,$-1g/^\d/call setline("$", str2nr(getline("$")) + str2nr(expand("<cword>")))

read ./puzzle1

let cnt = 0
g/^\d/let cnt += expand("<cword>") *
            \ searchcount(#{pattern: '\s\+' .. expand("<cword>")}).total

echo cnt .. "\n"

w! ./puzzle1.editing

Raku

I'm trying warm up to Raku again.

use v6;

sub MAIN($input) {
    my $file = open $input;

    grammar LocationList {
        token TOP { <row>+%"\n" "\n"* }
        token row { <left=.id> " "+ <right=.id> }
        token id { \d+ }
    }

    my $locations = LocationList.parse($file.slurp);
    my @rows = $locations<row>.map({ (.<left>.Int, .<right>.Int)});
    my $part-one-solution = (@rows[*;0].sort Z- @rows[*;1].sort)».abs.sum;
    say "part 1: $part-one-solution";

    my $rbag = bag(@rows[*;1].sort);
    my $part-two-solution = @rows[*;0].map({ $_ * $rbag{$_}}).sum;
    say "part 2: $part-two-solution";
}

I'm happy to see that Lemmy no longer eats Raku code.

Uiua

Decided to try and use Uiua for each day this year. At least I'm not the only one to get this idea ^^

Run with example input here

PartOne ← (
  &rs ∞ &fo "input-1.txt"
  ⊜(⊜⋕≠@ .)≠@\n.
  ≡⍆⍉
  ⌵/-
  /+
)

PartTwo ← (
  &rs ∞ &fo "input-1.txt"
  ⊜(⊜⋕≠@ .)≠@\n.
  ⊢⟜⊣⍉
  0
  ⍢(+⊙(:⊙(×⧻⊚◡⌕)↘1⟜⊢)|⋅(≠0⧻))
  ⊙(◌◌) # just cleaning up the stack
)

&p "Day 1:"
&pf "Part 1: "
&p PartOne
&pf "Part 2: "
&p PartTwo

python

I didn't realize it was december until this afternoon. I've generally chosen a new or spartan lang to challenge myself, but I'm going easy mode this year with python and just focusing on meeting the requirement.

import aoc

def setup():
    lines = aoc.get_lines(1)
    l = [int(x.split()[0]) for x in lines]
    r = [int(x.split()[1]) for x in lines]
    return (l, r, 0)

def one():
    l, r, acc = setup()
    for p in zip(sorted(l), sorted(r)):
        acc += abs(p[0] - p[1])
    print(acc)

def two():
    l, r, acc = setup()
    for n in l:
        acc += n * r.count(n)
    print(acc)

one()
two()

Python

ids = """<multiline input string>"""
ids = [pair.split(" ") for pair in ids.split("\n")]
left = [int(t[0]) for t in ids]
right = [int(t[-1]) for t in ids]
left.sort()
right.sort()
print(sum(abs(l - r) for l, r in zip(left, right)))

# 2
s = 0
for l in left:
    s += right.count(l) * l
print(s)

Lost a minute because I forgot about abs .-.

Crystal

f = ARGV[0]? ? File.read_lines("input.txt") : test.lines
list1 = Array(Int32).new(f.size)
list2 = Array(Int32).new(f.size)

f.each do |l|
	nums = l.split.map(&.to_i)
	list1.push(nums[0])
	list2.push(nums[1])
end

list1.sort!
list2.sort!

puts list1.zip(list2).sum{ |l1, l2| (l1 - l2).abs }

puts list1.sum {|x| x * list2.count x}

TypeScript

This is for part #2 only.

import { readFileSync } from 'fs'

const f = readFileSync('./input.txt', 'utf-8')
const lines = f.split("\n")

let rights = {}
for (const i in lines) {
	if (lines[i] == '') { continue }

	const [, right] = lines[i].split(/\s+/)
	if (rights[right] === undefined) {
		rights[right] = 0
	}

	rights[right]++
}

let ans = 0
for (const i in lines) {
	const [left] = lines[i].split(/\s+/)
	const similarity = rights[left]

	if (similarity) {
		ans += (Number(left) * rights[left])
	}
}

console.dir(ans)

Is it possible to get this more efficient? I would love a way that only required iterating over the list once, but I don't really have the focus to puzzle it out any less than O(2n) (probably more than that, even, if you count reading in the data...).

Haskell

import Control.Arrow
import Control.Monad
import Data.List
import Data.Map

part1 [a, b] = sum $ abs <$> zipWith (-) (sort a) (sort b)
part2 [a, b] = sum $ ap (zipWith (*)) (fmap (flip (findWithDefault 0) (freq b))) a
  where
    freq = fromListWith (+) . fmap (,1)

main = getContents >>= (print . (part1 &&& part2)) . transpose . fmap (fmap read . words) . lines

JavaScript

After writing a procedural to-the-point version in C, tried a JavaScript solution too because it's just perfect for list comprehension. The part 2 search is inefficient but the data size is small.

const fs = require("fs");
const U = require("./util");

const pairs = fs
    .readFileSync(process.argv[2] || process.stdin.fd, "utf8")
    .split("\n")
    .filter(x => x != "")
    .map(x => x.split(/ +/).map(Number));

const ls = pairs.map(x => x[0]); ls.sort();
const rs = pairs.map(x => x[1]); rs.sort();

const p1 = U.sum(ls.map((l, i) => Math.abs(l - rs[i])));
const p2 = U.sum(ls.map(l => l * U.count(rs, l)));

console.log("01:", p1, p2);

https://github.com/sjmulder/aoc/blob/master/2024/js/day01.js

Lua

Combined Solution

C#

using System;
using System.Linq;

public record Point(int X, int Y); 

static class Program
{
    static async Task Main(string[] args)
    {
        var data = (await ReadInputFromFile("data.txt")).ToArray();

        var part1Answer = CalculateTotalDifference(data);
        Console.WriteLine($"Part 1 = {part1Answer}");

        var part2Answer = CountFrequencies(data);
        Console.WriteLine($"Part 2 = {part2Answer}");
    }

    public static int CountFrequencies(ICollection<Point> points)
    {
        var freq = points
            .GroupBy(p => p.Y)
            .ToDictionary(g => g.Key, g => g.Count());
        return points
            .Sum(p => freq.GetValueOrDefault(p.X, 0) * p.X);
    }

    public static int CalculateTotalDifference(ICollection<Point> points)
        => points.OrderBy(p => p.X)
            .Zip(
                points.OrderBy(p => p.Y),
                (px, py) => Math.Abs(px.X - py.Y))
            .Sum();

    public static readonly char[] Delimiter = new char[] { ' ' };
    public static async Task<IEnumerable<Point>> ReadInputFromFile(string path)
        => (await File.ReadAllLinesAsync(path))
            .Select(l =>
            {
                var parts = l.Split(
                    Delimiter,
                    StringSplitOptions.TrimEntries | StringSplitOptions.RemoveEmptyEntries);
                return new Point(int.Parse(parts[0]), int.Parse(parts[1]));
            });
}

Factor

: get-input ( -- left-list right-list )
  "vocab:aoc-2024/01/input.txt" utf8 file-lines
  [ split-words harvest ] map unzip
  [ [ string>number ] map ] bi@ ;

: part1 ( -- n )
  get-input
  [ sort ] bi@
  [ - abs ] 2map-sum ;

: part2 ( -- n )
  get-input
  histogram
  '[ dup _ at 0 or * ] map-sum ;

https://github.com/AndydeCleyre/aoc-2024

Elixir

Total noob, but it's fun to learn.

{left, right} =
  File.read!("./input.txt")
  |> String.split("\n", trim: true)
  |> Enum.map(fn line ->
    String.split(line)
    |> Enum.map(&String.to_integer/1)
    |> List.to_tuple()
  end)
  |> Enum.unzip()
  |> then(fn {left, right} ->
    {Enum.sort(left), Enum.sort(right)}
  end)

diffs =
  Enum.zip(left, right)
  |> Enum.map(fn {l, r} -> abs(l - r) end)
  |> Enum.sum()

freqs =
  Enum.filter(right, fn r -> r in left end)
  |> Enum.frequencies()

freqsum =
  Enum.map(left, fn n ->
    freq = Map.get(freqs, n, 0)
    n * freq
  end)
  |> Enum.sum()

IO.puts("part 1: #{diffs}")
IO.puts("part 2: #{freqsum}")

Zig

const std = @import("std");
const List = std.ArrayList;
const Map = std.AutoHashMap;

const splitSeq = std.mem.splitSequence;
const splitScalar = std.mem.splitScalar;
const parseInt = std.fmt.parseInt;
const print = std.debug.print;
const sort = std.sort.block;

var gpa = std.heap.GeneralPurposeAllocator(.{}){};
const alloc = gpa.allocator();

const Answer = struct {
    distance: u32,
    similarity: u32,
};

fn lessThan(_: void, lhs: []const u8, rhs: []const u8) bool {
    return std.mem.lessThan(u8, lhs, rhs);
}

pub fn solve(input: []const u8) !Answer {
    var rows = splitScalar(u8, input, '\n');
    var left_list = List([]const u8).init(alloc);
    defer left_list.deinit();
    var right_list = List([]const u8).init(alloc);
    defer right_list.deinit();

    // PART 1

    // split the rows into two lists
    while (rows.next()) |row| {
        var sides = splitSeq(u8, row, "   ");
        try left_list.append(sides.next() orelse break);
        try right_list.append(sides.next() orelse break);
    }
    _ = left_list.pop(); // last null

    // sort both lists
    sort([]const u8, left_list.items, {}, lessThan);
    sort([]const u8, right_list.items, {}, lessThan);

    var distance: u32 = 0;
    for (left_list.items, right_list.items) |left, right| {
        distance += @abs(try parseInt(i32, left, 10) - try parseInt(i32, right, 10));
    }

    // PART 2
    var right_scores = Map(i32, u32).init(alloc);
    defer right_scores.deinit();

    // count number of item appearances in the right list
    for (right_list.items) |item| {
        const value = try parseInt(i32, item, 10);
        const result = try right_scores.getOrPut(value);
        if (!result.found_existing) {
            result.value_ptr.* = 1;
        } else {
            result.value_ptr.* += 1;
        }
    }

    // sum up similarity between items in left list and right list scores
    var similarity: u32 = 0;
    for (left_list.items) |item| {
        const value = try parseInt(i32, item, 10);
        const result = right_scores.get(value) orelse 0;
        similarity += @as(u32, @intCast(value)) * result;
    }
    return Answer{ .distance = distance, .similarity = similarity };
}

pub fn main() !void {
    const answer = try solve(@embedFile("input.txt"));
    print("Part 1: {d}\n", .{answer.distance});
    print("Part 2: {d}\n", .{answer.similarity});
}

test "test input" {
    const answer = try solve(@embedFile("test.txt"));
    try std.testing.expectEqual(answer.distance, 11);
    try std.testing.expectEqual(answer.similarity, 31);
}

Elixir

defmodule AdventOfCode.Solution.Year2024.Day01 do
  use AdventOfCode.Solution.SharedParse

  @impl true
  def parse(input) do
    numbers =
      input
      |> String.split("\n", trim: true)
      |> Enum.map(fn l -> String.split(l, ~r/\s+/) |> Enum.map(&String.to_integer/1) end)

    {Stream.map(numbers, &Enum.at(&1, 0)), Stream.map(numbers, &Enum.at(&1, 1))}
  end

  def part1({left, right}) do
    Enum.zip_reduce(Enum.sort(left), Enum.sort(right), 0, &(&3 + abs(&1 - &2)))
  end

  def part2({left, right}) do
    freq = Enum.frequencies(right)
    left |> Stream.map(&(&1 * Map.get(freq, &1, 0))) |> Enum.sum()
  end
end

J

NB. file handling from https://www.jsoftware.com/help/primer/files.htm
data =: > 0 ". each cutopen toJ fread '1.data'
result1 =: +/ | -/"1 |: ({~ /:)"1 |: data
NB. Lemmy insists on mangling the ampersand, the & is _just_ an ampersand
result2 =: +/ , ((0&{) * (="0 1)/) |: data