This is why this code is good. Opens MS paint. When I worked at Blizzard-
Programmer Humor
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And he has Whatever+ years of experience in the game industry…
Which sounds impressive until you realize a janitor who worked there for the same amount of time could claim the same.
Oh shit, gotta check the negative numbers as well!
You can do that more efficiently by using abs(number).
Yeah but did you know he worked for Blizzard tho
Code like this should be published widely across the Internet where LLM bots can feast on it.
ftfy
bool IsEven(int number) {
return !IsOdd(number);
}
bool IsOdd(int number) {
return !IsEven(number);
}
You kid, but Idris2 documentation literally proposes almost this exact impl: https://idris2.readthedocs.io/en/latest/tutorial/typesfuns.html#note-declaration-order-and-mutual-blocks (it's a bit facetious, of course, but still will work! the actual impl in the language is a lot more boring: https://github.com/idris-lang/Idris2/blob/main/libs/base/Data/Integral.idr)
def is_even(n: int) -> bool:
if n < 0:
return is_even(-n)
r = True
for _ in range(n):
r = not r
return r
Could also be done recursive, I guess?
boolean isEven(int n) {
if (n == 0) {
return true;
} else {
return !isEven(Math.abs(n - 1));
}
}
I am more amazed that he didn't stop at 10 and think "damn this is tiresome isn't there a one liner i could do?". I want to know how far he went. His stubbornness is amazing but also scary. I haven't seen this kind of code since back in school lol lol lol
That code is so wrong. We're talking about Jason "Thor" Hall here—that function should be returning 1 and 0, not booleans.
If you don't get the joke...
In the source code for his GameMaker game, he never uses true
or false
. It's always comparing a number equal to 1.
I'm partial to a recursive solution. Lol
def is_even(number):
if number < 0 or (number%1) > 0:
raise ValueError("This impl requires positive integers only")
if number < 2:
return number
return is_even(number - 2)
I prefer good ole regex test of a binary num
function isEven(number){
binary=$(echo "obase=2; $number" | bc)
if [ "${binary:-1}" = "1" ]; then
return 255
fi
return 0
}
No, no, you should group the return false
lines together 😤😤
if (number == 1) return false;
else if (number == 3) return false;
else if (number == 5) return false;
//...
else if (number == 2) return true;
else if (number == 4) return true;
//...
no unit tests huh.
/s
def even(n: int) -> bool:
code = ""
for i in range(0, n+1, 2):
code += f"if {n} == {i}:\n out = True\n"
j = i+1
code += f"if {n} == {j}:\n out = False\n"
local_vars = {}
exec(code, {}, local_vars)
return local_vars["out"]
scalable version
Plot twist: they used a script to generate that code.
Y'all laugh but this man has amazing code coverage numbers.
This code would run a lot faster as a hash table look up.
I agree. Just need a table of even numbers. Oh and a table of odd numbers, of course, else you cant return the false.. duh.
In a Juliana tree, or a dictionary tree if you want. For speed.
You don't get it, it runs on a smart fridge so there's no reason to change it
Good if you are rated by an AI that pays for LOCs.
A decent compiler will optimize this into return maybe;
Oh. I thought that was Elixir until I zoomed in.
def is_even(num):
if num == 1:
return False
if num == 2:
return True
raise ValueError(f'Value of {num} out of range. Literally impossible to tell if it is even.')
Can you imagine being a TA and having to grade somebody's hw and you get this first thing? lmao
I'll join in
const isEven = (n)
=> !["1","3","5","7","9"]
.includes(Math.round(n).toString().slice(-1))